Недавно мне подкинули задачку, надо решить её средствами java

В общем условие такое:

Есть две переменные i и k

надо задать им тип и проинициализировать так чтобы нижеследующий цикл стал бесконечным:

while (i<=k && k<=i && k!=i) {

// do somthing

}

вот, - я бился над этим, но так ничего не придумал.

Мне уже просто интересно - какое ж решение?

Читал про wraper(ы) примитивов и долго не мог въехать в пример и его объяснения. Когда въехал то понял хде собака порылась:)

В общем вот решение(кто не верит, запустите под java 5):

        Integer i = 1000;
        Integer k = 1000;
        while (i<=k && k<=i && k!=i) {
            // dp something
        }

А вот вам объяснение:

look at how wrappers work with ==, !=, and equals(). We'll talk a lot more about

the equals() method in later chapters. For now all we have to know is that the

intention of the equals() method is to determine whether two instances of a given

class are "meaningfully equivalent." This definition is intentionally subjective; it's

up to the creator of the class to determine what "equivalent" means for objects of the

class in question. The API developers decided that for all the wrapper classes, two

objects are equal if they are of the same type and have the same value. It shouldn't

be surprising that

meaningfully equal

have the same int value, the equals() method considers them to be "meaningfully

equivalent", and therefore returns true. How about this one:

Yikes! The equals() method seems to be working, but what happened with ==

and != ? Why is != telling us that i1 and i2 are different objects, when == is saying

that i3 and i4 are the same object? In order to save memory, two instances of the

following wrapper objects will always be == when their primitive values are the same:

n Boolean

n Byte

n Character from \u0000 to \u007f (7f is 127 in decimal)

n Short and Integer from -128 to 127